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Side Effects of Prevnar – Hypothesis Test for a Proportion
Example: The drug Prevnar is a vaccine meant to prevent meningitis. (It also
helps control ear infections.) It is typically administered to infants. In
clinical trials, the vaccine was administered to 710 randomly sampled infants
between 12 and 15 months of age. Of the 710 infants, 121 experienced a decrease
in appetite. Is there significant evidence to conclude that the proportion of
infants who receive Prevnar and experience a decrease in appetite is different
from 0.135, the proportion of children who experience a decrease in appetite in
competing medications? Test using the P-value approach at the
level
of significance.
This
hypothesis test is a two-tailed test of:
vs.
.
The procedure that is used for this test is the 1-Proportion Test. This test
has two requirements. The first requirement is:
To
verify this, calculate 710*.135*(1-.135). The result is greater than 10, so
the first requirement is satisfied. The second requirement is that the sample
size is not more than 5% of the population size. In this example, the
population is all babies between 12 and 15 months of age. We don’t know the
exact size of the population, but it is in the millions. The sample size of 710
is definitely less than 5% of the population size.
To run
the test, press STAT, highlight TESTS and select 5:1-PropZtest. This test
requires a value for
,
which is the value of p in the null hypothesis. Enter .135 for
.
Next, a value for X is required. X is the number of “successes” in the sample.
In this example, a success is “experiencing a decrease in appetite”, so X is
equal to 121. Next, enter the value for n. Select
for
the alternative hypothesis and press ENTER.
Highlight Calculate and press ENTER.
The
output displays the alternate hypothesis that was selected, the calculated
Z-value, the P-value, the sample proportion,
,
and the sample size. (Note:
=121/710.)
Or, highlight Draw and press ENTER.
Since
the P-value is less than a, the correct conclusion is to Reject
.